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2020秋高数上期末(回忆版)

Multiple Choice Questions: (only one correct answer for each of the following questions.)

1-1

The number of the real roots for the equation x33x+3=0 is

(A) 0

(B) 1

(C) 2

(D) 3

1-2

If f(x) is continuous on (,+), which of the following statements is wrong?

(A) 01f(x)dx=01f(t)dt

(B) 01f(x)dx=01f(sinx)d(sinx)

(C) d(0xf(t)dt)=f(x)dx

(D) d(0x2f(t)dt)=f(x2)d(x2)

1-3

Let f(x)={x4sin1xx00,x=0

Then the largest positive integer n, for which f(n)(0) exists, is

(A) 1

(B) 2

(C) 3

(D) 4

1-4

If f(x) is twice-differentiable on (,+), and g(x)=(1x)f(0)+xf(1), then which of the following statements is correct on (0,1) ?

(A) f(x)>g(x) if f(x)>0

(B) f(x)>g(x) if f(x)<0

(C) f(x)>g(x) if f(x)>0

(D) f(x)>g(x) if f(x)<0

1-5

If the improper integal 0+tan1(x2)xkdx converges, then the constant k must satisfy

(A) k<1

(B) k>3

(C) 1<k<2

(D) 1<k<3

Fill in the blanks

2-1

function f(x)=x2 has a tangent line y=kx1 if k= , or

2-2

Assume that f(0)=3,f(0)=5,f(1)=4, and f(1)=7 .Let g(x)=f(lnx) .Then g(1)=

2-3

The average value for f(x)=sin3x on [0,π] is

2-4

Let y=(cosx)x for 0<x<π2, then y(x)=

2-5

If f(a) exists, and f(a)0, then limxa(1f(a)(xa)1f(x)f(a))=

The region D is enclosed by the curve y=lnx1, the straight line x=5, and the x-axis

3-1

Find the area of the region D

3-2

Find the volumes generated by revolving the region D about the line x=5

Find the particular solution of

xy+(x2)y=3x3ex,x>0

satisfying y(1)=0

Evaluate the following limits

5-1

limn+(n2n2+3n+12+n2n2+6n+22+n2n2+3nk+k2++n2n2+3n2+n2)

5-2

limx0(ln(1+x)x)1ex1

6-1

For y=x2+1x+1, identify the coordinates of any local and absolute extreme points and inflection points that may exist

6-2

Sketch the graph of the above function. (Please identify all the asymptotes and some specific points, such as local maximum and minimum points, inflection points, and intercepts.)

Find dydx if y=x2+12x2+3ttanx+tdt

Evaluate the integrals

8-1

π3π6csc3xxdx

8-2

xx2dx, where x>2

8-3

1eln3xdx

8-4

1+(x+2)ln(x2+1)x3dx

Let f(n)=m=1n0mcos2πnx+1mdx, here x+1 is the largest integer which is less than or equal to x+1. Evaluate f(2021)